Tutorial: A few useful videos
#1
Posted 03 September 2008 - 09:59 PM
Basic speaker parts
How to ground your amp
Bass boost demonstration
Cross over basics (HP vs. LP)
How to build a box
How to carpet a box
Gain setting
Building a kick panel
Series vs. parrallel
Big 3 upgrade
Installing ring terminals
How NOT to wire your speakers
How to make custom RCA cables
Installing component speakers
Mechancal vs. thermal power handling
#2
Posted 05 September 2008 - 11:36 PM
Anyone have links to other vids?
#3
Posted 12 September 2008 - 04:05 PM
In regards to the "gain setting" vid, they run a test tone at 50Hz and then use a multimeter to check the voltage output. They start off at about 14V and they want to get it to 40V. They then turn the gain up til they reach 40V.
My question is - Why 40V??
#4
Posted 13 September 2008 - 12:10 AM
Interesing vids
I watched most of them
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In regards to the "gain setting" vid, they run a test tone at 50Hz and then use a multimeter to check the voltage output. They start off at about 14V and they want to get it to 40V. They then turn the gain up til they reach 40V.
My question is - Why 40V??
The speaker that they will be hooking in up to is a 4ohm speaker (hence the 4ohm resistor that they use). The speaker would have a power handling at around 400W. Using the rule to determine power (P=V^2/R) they determine what voltage they need from the amps output.
400/4=V^2
V=sqrt(400/4)
V=40
#5
Posted 15 September 2008 - 09:19 AM
So, if i have a monoblock that can put out 1800wrms and that is powering 2 subs that present a 1 Ohm load...
V = sqrt(1800/1)
V = 42.42
#7
Posted 17 September 2008 - 02:15 AM
Ahhh ok
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So, if i have a monoblock that can put out 1800wrms and that is powering 2 subs that present a 1 Ohm load...
V = sqrt(1800/1)
V = 42.42
Yes thats correct, but you may not need all the amps power (1800W in your case), the amps output current should depend on the power handling on your subs, and how they are wired. So as your subs have a power handling of 600 watt each, then giving it the full 1800 could cause some damage to them. Best option would be to have an output of 34.64V from your amp as it will then be producing 1200W.
Edited by joey4, 18 September 2008 - 01:33 PM.
#8
Posted 18 September 2008 - 08:46 AM
Also, there was a slight error in your calculations.
It should be V = sqrt (P x R), instead of sqrt(P/R). You still had the V figure right tho
#9
Posted 13 October 2008 - 11:49 PM
#10
Posted 17 October 2008 - 06:37 PM
#11
Posted 26 November 2010 - 08:28 AM
#12
Posted 28 November 2010 - 12:34 PM













